A RCC beam of rectangular section 250 mm wide and 600 mm deep (effective) is reinforced on tension side by 4 bars of 20 mm diameter. The beam is subjected to mild exposure conditions. Use M20 and Fe415 grade materials.
(i) Calculate ultimate moment of resistance of beam.
(ii) Determine the maximum u.d.l., a simply supported beam can carry over a span of 6 m.
Given Data:
- Width of the beam (b) = 250 mm
- Effective depth of the beam (d) = 600 mm
- Number of tension bars = 4
- Diameter of tension bars (Γ) = 20 mm
- Grade of concrete = M20 (fck = 20 MPa)
- Grade of steel = Fe415 (fy = 415 MPa)
- Span of the beam (L) = 6 m
- Mild exposure conditions
Step 1: Calculate the area of tensile reinforcement (Ast)
The area of one bar is given by:
π΄bar=π4Γπ2
Substituting π=20 mm:
π΄bar=π4Γ(20)2=314.16βmm2
Thus, the total area of steel (Ast):
π΄st=4Γ314.16=1256.64βmm2
Step 2: Check if the section is under-reinforced or over-reinforced
For an under-reinforced section, the design moment of resistance is governed by the tension steel reaching its yield strength.
Calculate the neutral axis depth factor π₯π’/π. The limiting value for Fe415 steel is:
π₯π’,limπ=0.48(for Fe415)
Hence, the limiting depth of the neutral axis is:
π₯π’,lim=0.48Γ600=288βmm
Now, calculate the actual depth of the neutral axis using the equation:
π΄stβ ππ¦0.36β πππβ π=π₯π’
Substituting the values:
1256.64Γ4150.36Γ20Γ250=π₯π’=241.54βmm
Since π₯π’<π₯π’,lim, the section is under-reinforced.
Step 3: Calculate the ultimate moment of resistance (Mu)
The ultimate moment of resistance for an under-reinforced section is given by:
ππ’=0.87β ππ¦β π΄stβ (πβ0.42β π₯π’π)
Substitute the values:
ππ’=0.87Γ415Γ1256.64Γ(600β0.42Γ241.54)Γ10β6ππ’=453.38βkNm
Step 4: Determine the maximum uniform distributed load (w)
For a simply supported beam with span πΏ, the maximum moment due to a UDL is given by:
ππ’=π€β πΏ28
Rearrange to solve for π€:
π€=8β ππ’πΏ2
Substituting the values:
π€=8Γ453.38Γ106(6000)2=100.75βkN/m
Final Answers:
- Ultimate moment of resistance ππ’ = 453.38 kNm
- Maximum UDL the beam can carry = 100.75 kN/m
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