Highway Engineering · Engineering Surveys · Detailed Calculations · GATE CE · SSC JE Civil · IRC SP-19 · IS 1498
IRC SP-19 — Manual for Survey, Investigation & Preparation of Road Projects |
IRC 73 : 1980 — Geometric Design of Rural Highways |
IS 1498 — Classification of Soils for General Engineering Purposes |
MoRTH Specifications 5th Rev.
📋 Table of Contents
- Introduction — What are Engineering Surveys for Highways?
- Reconnaissance Survey — Process & Instruments
- Preliminary Survey — Detailed Process & Calculations
- Levelling — Theory, Types & Worked Example
- Cross-Section Survey — Process & Area Calculations
- Earthwork Calculations — Prismoidal & Average End Area Method
- Mass Haul Diagram — Theory & Worked Example
- Final Location (Detailed) Survey — Step-by-Step Process
- Curve Setting Out — Deflection Angle Method (with Calculation)
- Soil Investigation Survey — CBR & Subgrade Testing
- Drainage Survey — Catchment Area & Culvert Sizing
- Modern Survey Methods — Total Station, GPS, LiDAR, UAV
- Technical Diagrams
- Key Formulas & Keywords
- GATE & SSC JE Solved MCQs
- Frequently Asked Questions (FAQs)
1. Introduction — What are Engineering Surveys for Highways?
As a highway engineer who has cleared both GATE CE and SSC JE Civil, I want you to understand that engineering surveys are the backbone of every highway project. Before a single bucket of soil is moved, engineers spend months surveying the terrain, measuring levels, testing soils, calculating earthwork volumes, and locating drainage structures. Without accurate surveys, a highway project cannot be designed, estimated, tendered, or built.
Engineering surveys for highways are the systematic collection of field data required to plan, design, and construct a road. They include:
- Measuring the exact position of the centreline (traverse survey)
- Determining ground elevations along and across the centreline (levelling)
- Measuring cross-sections to calculate earthwork volumes
- Investigating soil and subgrade conditions (geotechnical survey)
- Assessing drainage requirements (hydrological survey)
- Setting out curves and gradients on the ground (layout survey)
The survey data feeds directly into the Detailed Project Report (DPR), Bill of Quantities (BOQ), and construction drawings. Every calculation in this post is exam-ready — solved step by step.
2. Reconnaissance Survey — Process & Instruments
2.1 Purpose
The reconnaissance survey is a rapid field inspection to identify feasible route options and eliminate obviously unsuitable corridors. It follows the map study (desk study) and precedes the preliminary survey.
2.2 Step-by-Step Process
- Desk study — Study SOI topo maps (1:50,000), satellite imagery (Cartosat/Google Earth), geological maps, forest maps. Mark 3–4 possible corridors on the map.
- Field walk-over — Travel along each corridor by jeep/foot/helicopter. Observe terrain, drainage, soil colour, settlements, existing structures.
- Sketching — Draw rough plan of each route with key features (rivers, hills, villages, problem areas).
- Photography — Document key locations, problem areas, crossing points.
- Approximate levelling — Use aneroid barometer or hand level to estimate elevation differences at critical points.
- Report preparation — Write reconnaissance report with rough plan, estimated length, major obstacles, and preliminary cost estimate.
2.3 Instruments in Reconnaissance Survey
| Instrument | Use | Accuracy |
|---|---|---|
| Aneroid Barometer | Approx. elevation difference between points | ±3–5 m |
| Prismatic Compass | Magnetic bearings and direction of routes | ±30′ |
| Hand Level (Abney Level) | Quick slope angle and gradient measurement | ±0.5° |
| Odometer / Measuring Wheel | Distance measurement along route | ±0.5% |
| Handheld GPS | Record coordinates of key points | ±3–5 m |
| Camera / Drone | Documentation of terrain, obstacles | Visual |
3. Preliminary Survey — Detailed Process & Calculations
3.1 Purpose & Scope
The preliminary survey is an instrument-based survey of the 2–3 selected route corridors. It generates enough data to technically compare routes and recommend the best one. It is conducted at a scale of 1:10,000 to 1:50,000.
3.2 Step-by-Step Process
- Control traverse — Establish a series of traverse stations (T1, T2, T3…) along each candidate route using theodolite + tape or total station. Measure horizontal angles and distances.
- Levelling (L-section) — Run a level circuit from a Benchmark (BM) along the traverse stations. Record staff readings to determine ground levels at every 20–50 m chain interval. Plot the longitudinal section (L-section).
- Cross-sectioning — At every 20–50 m chainagepeg, take levels at right angles to the centreline at offsets of 5, 10, 15, 20 m (or to the toe of embankment/top of cutting).
- Soil investigation — Dig trial pits every 500 m to a depth of 1.5–2.0 m. Collect disturbed samples for classification (IS 1498) and CBR testing.
- Drainage survey — Identify all watercourses crossing the route. Measure catchment areas using maps. Record HFL (High Flood Level) marks on trees/structures.
- Traffic survey — Count traffic on existing parallel roads to estimate design traffic for the new highway.
- Plotting and earthwork calculation — Plot the L-section, fix the proposed grade line, calculate cut/fill areas from cross-sections, draw mass haul diagram.
- Cost estimation and comparison — Estimate cost of each route. Prepare a comparative statement and recommend the best route.
4. Levelling — Theory, Types & Worked Example
4.1 What is Levelling in Highway Survey?
Levelling is the process of determining the difference in elevation between points along the highway route. The result is plotted as a Longitudinal Section (L-Section), which shows the existing ground profile and the proposed grade line of the road.
4.2 Key Levelling Terms
- Benchmark (BM) — A fixed reference point of known elevation (from Survey of India GTS Benchmarks)
- Instrument Station (IS) — Position where the levelling instrument is set up
- Back Sight (BS) — First staff reading taken after instrument is set up (on BM or change point)
- Fore Sight (FS) — Last staff reading taken before moving the instrument (on change point)
- Intermediate Sight (IS) — Any staff reading between BS and FS
- Height of Instrument (HI) — Elevation of the line of sight = RL of station + BS reading
- Reduced Level (RL) — Elevation of any point = HI − staff reading at that point
- Change Point (CP) — A point where both FS and BS are taken; used when instrument is moved
4.3 Methods of Reducing Levels
- Height of Instrument (HI) Method — Fast; used when there are many intermediate sights; preferred for highway L-sections
- Rise and Fall Method — More checks; preferred for precise levelling; arithmetic check: ΣBS − ΣFS = ΣRise − ΣFall = Last RL − First RL
4.4 ✏️ Worked Example — Height of Instrument Method
A levelling survey is conducted along a highway route starting from BM (RL = 100.000 m). The following staff readings were recorded:
| Station | Chainage (m) | BS (m) | IS (m) | FS (m) | HI (m) | RL (m) | Remarks |
|---|---|---|---|---|---|---|---|
| BM | 0 | 1.485 | — | — | 101.485 | 100.000 | BM (known RL) |
| A | 20 | — | 1.320 | — | 101.485 | 100.165 | IS |
| B | 40 | — | 0.985 | — | 101.485 | 100.500 | IS |
| CP1 | 60 | 2.120 | — | 1.875 | 101.730 | 99.610 | Change Point |
| C | 80 | — | 1.450 | — | 101.730 | 100.280 | IS |
| D | 100 | — | — | 0.990 | 101.730 | 100.740 | FS (end) |
Step-by-Step Calculations:
HI₁ = RL(BM) + BS = 100.000 + 1.485 = 101.485 m
RL(A) = HI₁ − IS(A) = 101.485 − 1.320 = 100.165 m
RL(B) = HI₁ − IS(B) = 101.485 − 0.985 = 100.500 m
RL(CP1) [FS] = HI₁ − FS(CP1) = 101.485 − 1.875 = 99.610 m
Setup 2 (at CP1, Chainage 60):
HI₂ = RL(CP1) + BS = 99.610 + 2.120 = 101.730 m
RL(C) = HI₂ − IS(C) = 101.730 − 1.450 = 100.280 m
RL(D) = HI₂ − FS(D) = 101.730 − 0.990 = 100.740 m
Arithmetic Check (HI Method):
ΣBS = 1.485 + 2.120 = 3.605
ΣFS = 1.875 + 0.990 = 2.865
ΣBS − ΣFS = 3.605 − 2.865 = 0.740
Last RL − First RL = 100.740 − 100.000 = 0.740 ✅ (Check satisfied)
5. Cross-Section Survey — Process & Area Calculations
5.1 What is Cross-Sectioning?
A cross-section is a section of the ground taken at right angles to the centreline of the highway at regular intervals (every 10–30 m). Cross-sections show the shape of the ground across the road width. When the road grade line is overlaid, the area between the ground and grade line is either a cutting (cut) or an embankment (fill).
5.2 Types of Cross-Sections
- Level section — Ground is level across the carriageway (flat terrain)
- Two-level section — Ground slopes in one direction (side slope)
- Three-level section — Ground slopes differently on each side of centreline
- Multi-level (irregular) section — Complex ground; calculated using coordinate method
5.3 ✏️ Worked Example — Cross-Section Area (Level Section)
Given data:
Formation width (B) = 7.0 m (2-lane NH)
Side slopes: Cut = 1:1 (1H:1V), Fill = 1.5:1 (1.5H:1V)
Depth of cutting at centreline (h) = 2.5 m
Find: Area of cross-section in cutting
Area = (B + nh) × h
where B = formation width, n = side slope ratio (H:V = n:1), h = depth of cut
A = (7.0 + 1×2.5) × 2.5
A = (7.0 + 2.5) × 2.5
A = 9.5 × 2.5
A = 23.75 m²
5.4 ✏️ Worked Example — Two-Level Section (Side Slope Ground)
Given data:
Formation width (B) = 7.0 m | Formation half-width = b = B/2 = 3.5 m
Depth at centreline h = 1.8 m
Ground cross-slope = 1 in 10 (i.e., s = 10)
Side slope of cutting n = 1:1 (n = 1)
Find: Area of cross-section
W₁ = (b + nh) × s / (s − n) [width on lower side]
W₂ = (b + nh) × s / (s + n) [width on upper side]
h₁ = h + b/s = 1.8 + 3.5/10 = 1.8 + 0.35 = 2.15 m [depth on lower side]
h₂ = h − b/s = 1.8 − 3.5/10 = 1.8 − 0.35 = 1.45 m [depth on upper side]
Area = (1/2) × (W₁ × h₁ + W₂ × h₂)
W₁ = (3.5 + 1×1.8) × 10 / (10 − 1) = 5.3 × 10/9 = 5.889 m
W₂ = (3.5 + 1×1.8) × 10 / (10 + 1) = 5.3 × 10/11 = 4.818 m
Area = (1/2) × (5.889×2.15 + 4.818×1.45)
Area = (1/2) × (12.661 + 6.986)
Area = (1/2) × 19.647
Area = 9.82 m²
6. Earthwork Calculations — Prismoidal & Average End Area Methods
6.1 Average End Area Method
This is the most commonly used method in highway engineering. The volume of earthwork between two consecutive cross-sections is calculated as:
V = (A₁ + A₂)/2 × L
where A₁ = cross-section area at first station (m²)
A₂ = cross-section area at second station (m²)
L = distance between the two sections (m)
6.2 ✏️ Worked Example — Average End Area Method
Cross-section areas and chainages along a highway cutting are:
| Chainage (m) | Area (m²) | Distance L (m) | Avg Area (m²) | Volume (m³) |
|---|---|---|---|---|
| 0 | 0 | — | — | — |
| 20 | 12.5 | 20 | (0+12.5)/2 = 6.25 | 6.25×20 = 125 |
| 40 | 23.75 | 20 | (12.5+23.75)/2 = 18.125 | 18.125×20 = 362.5 |
| 60 | 18.00 | 20 | (23.75+18.00)/2 = 20.875 | 20.875×20 = 417.5 |
| 80 | 8.50 | 20 | (18.00+8.50)/2 = 13.25 | 13.25×20 = 265 |
| 100 | 0 | 20 | (8.50+0)/2 = 4.25 | 4.25×20 = 85 |
| Total Volume of Earthwork (Cutting) | 1,255 m³ | |||
6.3 Prismoidal Formula (More Accurate)
V = (L/6) × (A₁ + 4A_m + A₂)
where A_m = area of the middle cross-section (taken at the mid-point between the two sections)
L = length between the two end sections
Prismoidal Correction:
C_p = (L/12) × (D₁ − D₂)² × n
where D₁, D₂ = centre depths at two sections | n = side slope
Prismoidal volume = Average End Area volume − C_p (for cutting)
6.4 ✏️ Worked Example — Prismoidal Formula
Given: Two cross-sections 30 m apart. A₁ = 18 m², A₂ = 30 m², A_m (middle section) = 25 m²
V = (30/6) × (18 + 4×25 + 30)
V = 5 × (18 + 100 + 30)
V = 5 × 148
V = 740 m³
Compare with Average End Area:
V_avg = (18 + 30)/2 × 30 = 24 × 30 = 720 m³
Prismoidal correction = 740 − 720 = 20 m³
(Prismoidal is more accurate; Average End Area slightly underestimates for convex sections)
7. Mass Haul Diagram — Theory & Worked Example
7.1 What is a Mass Haul Diagram?
A mass haul diagram is a graph that shows the cumulative algebraic sum of earthwork volumes (cuts as positive, fills as negative) plotted against chainage. It is used to:
- Determine the most economical direction of hauling (moving) excavated material
- Identify where surplus cut material should be deposited (spoil banks) or where additional fill material (borrow) is needed
- Calculate haul distance and haul cost
- Balance cut and fill within an economical haul distance (free haul distance)
7.2 Key Terms
- Haul — The product of volume of earth moved × distance moved (unit: m³·m or station-m³)
- Free haul distance (FHD) — Distance within which earthwork is moved at no extra cost (typically 30 m in India)
- Overhaul distance — Distance beyond FHD; charged extra per unit haul
- Borrow — Earth imported from outside the project limits when fill exceeds cut
- Waste (Spoil) — Surplus cut material disposed outside project limits when cut exceeds fill
- Balancing point — Chainage where cumulative volume = 0 (cut and fill balance)
7.3 ✏️ Worked Example — Cumulative Volume (Mass Haul)
| Chainage (m) | Cut Volume (m³) | Fill Volume (m³) | Net Volume (m³) | Cumulative Volume (m³) | Remark |
|---|---|---|---|---|---|
| 0 | — | — | 0 | 0 | Start |
| 20 | +200 | — | +200 | +200 | Cutting |
| 40 | +350 | — | +350 | +550 | Cutting (peak) |
| 60 | — | −180 | −180 | +370 | Fill starts |
| 80 | — | −250 | −250 | +120 | Fill |
| 100 | — | −120 | −120 | 0 | Balanced! |
| 120 | — | −200 | −200 | −200 | Borrow needed |
• Rising curve = cutting zone (positive net volume being added)
• Falling curve = embankment/fill zone (volume being consumed)
• Peak = maximum surplus cut material available at that chainage
• Trough = maximum deficit — borrow material needed
• Where curve crosses zero line = balancing point (cut = fill up to that chainage)
8. Final Location (Detailed) Survey — Step-by-Step Process
8.1 Key Operations
- Reference traverse — Establish permanent control stations using total station; all subsequent work referenced to these
- Centreline pegging — Peg every 20 m (tangents) and 10 m (curves) with hardwood pegs + bamboo ranging rods
- Precise levelling — Fly levelling from GTS BM; establish TBMs (Temporary Bench Marks) every 200–300 m; reduced levels at every peg
- Cross-sections — At every 10–20 m; extend to toe of embankment or top of cutting ± extra 5 m
- Curve setting out — All horizontal curves set out using deflection angle method or total station coordinate method
- Structure locations — Mark culvert, bridge, retaining wall positions precisely
- Borrow pit survey — Identify borrow pits with adequate material; test CBR; calculate haul distance
- Utility survey — Electric lines, pipelines, telephone cables — mark for diversion
- Land Acquisition Plan (LAP) — Overlay road width on cadastral map; identify affected plots
9. Curve Setting Out — Deflection Angle Method (with Calculation)
9.1 What is the Deflection Angle Method?
The deflection angle method (Rankine’s method) is the most commonly used field method to set out a circular curve using a theodolite at the PC (Point of Curvature). It works by calculating successive deflection angles from the tangent at PC to each successive point on the curve.
9.2 Theory
δ = (chord length c × 1718.87) / R (in minutes)
or δ = c / (2R) radians = (c × 90) / (πR) degrees
where c = chord length (m), R = radius of curve (m)
Total deflection to nth point: Δₙ = n × δ
Total deflection = Δ/2 (half the deflection angle of the whole curve)
9.3 ✏️ Worked Example — Deflection Angle Method
Given:
Radius R = 300 m | Deflection angle Δ = 30° | Peg interval = 20 m
Find: Deflection angles for curve setting out (first 3 pegs + last peg at PT)
L = πRΔ/180 = π × 300 × 30/180 = 157.08 m
Step 2: Tangent Length
T = R × tan(Δ/2) = 300 × tan(15°) = 300 × 0.2679 = 80.38 m
Step 3: Deflection angle per 20 m chord
δ = (c × 1718.87) / R = (20 × 1718.87) / 300 = 114.59′ = 1°54’35”
Step 4: Tabulate deflection angles from PC
| Point | Chainage from PC (m) | Chord (m) | Incremental δ | Total Deflection from PC |
|---|---|---|---|---|
| PC | 0 | — | 0°00’00” | 0°00’00” |
| P1 | 20 | 20 | 1°54’35” | 1°54’35” |
| P2 | 40 | 20 | 1°54’35” | 3°49’10” |
| P3 | 60 | 20 | 1°54’35” | 5°43’45” |
| … (7 more) | … | 20 | 1°54’35” | … |
| PT | 157.08 | 17.08 (sub-chord) | — | 15°00’00” = Δ/2 ✅ |
10. Soil Investigation Survey — CBR & Subgrade Testing
10.1 Purpose
The soil investigation survey determines the type and engineering properties of the subgrade soil along the highway route. This data is used for pavement design (IRC 37 — flexible pavements; IRC 58 — rigid pavements) and embankment design.
10.2 Field Tests Conducted
- Trial pits — Dug every 500 m along centreline, depth 1.5–2.0 m; soil samples collected at each layer change
- Bore holes — At bridge sites, to depth of 5–15 m below scour level; SPT (Standard Penetration Test) at every 1.5 m
- In-situ CBR test (Dynamic Cone Penetrometer) — Quick field estimate of subgrade CBR
- Plate Bearing Test — For rigid pavement design (modulus of subgrade reaction K)
10.3 Laboratory Tests on Collected Samples
| Test | Standard | Parameter Obtained | Use |
|---|---|---|---|
| Grain size analysis | IS 2720 Part 4 | D10, D30, D60, Cu, Cc | Soil classification (IS 1498) |
| Atterberg Limits | IS 2720 Part 5 | LL, PL, PI, SL | Plasticity; suitability for subgrade |
| Proctor Compaction | IS 2720 Part 8 | OMC, MDD (γd max) | Compaction specification for earthwork |
| CBR Test (Soaked) | IS 2720 Part 16 | CBR value (%) | Pavement thickness design (IRC 37) |
| Free Swell Index | IS 2720 Part 40 | FSI (%) | Identify expansive (black cotton) soils |
| Shear Strength (UU Triaxial) | IS 2720 Part 11 | c, φ | Slope stability design for cuttings/embankments |
10.4 ✏️ Worked Example — Design CBR Calculation
CBR values from trial pits along a 5 km highway stretch are: 4, 6, 5, 8, 3, 5, 7, 4, 6, 5 %
n = 10 values
Step 2: Mean (x̄) = (3+4+4+5+5+5+6+6+7+8)/10 = 53/10 = 5.3%
Step 3: Standard Deviation (σ)
Variance = [(3−5.3)²+(4−5.3)²+(4−5.3)²+(5−5.3)²+(5−5.3)²+(5−5.3)²+(6−5.3)²+(6−5.3)²+(7−5.3)²+(8−5.3)²] / (n−1)
= [5.29+1.69+1.69+0.09+0.09+0.09+0.49+0.49+2.89+7.29] / 9
= 20.10 / 9 = 2.233
σ = √2.233 = 1.494 ≈ 1.5%
Step 4: Design CBR (IRC 37 recommends using 90th percentile or mean − 1.65σ for design)
Design CBR = x̄ − 1.65σ = 5.3 − 1.65×1.5 = 5.3 − 2.475 = 2.83% ≈ 3%
∴ Design CBR = 3% (use IRC 37 charts with CBR = 3% to determine pavement thickness)
11. Drainage Survey — Catchment Area & Culvert Sizing
11.1 Purpose
The drainage survey identifies all watercourses that need to be channelled under or around the highway through culverts, causeways, or bridges. Undersized drainage structures are the most common cause of highway failure in India.
11.2 Rational Method — Peak Discharge Calculation
Q = (C × i × A) / 360 [m³/s]
where C = runoff coefficient (0.3–0.9 depending on land use)
i = rainfall intensity for time of concentration (mm/hr)
A = catchment area (hectares or km² × 100 for hectares)
Note: For A in km²: Q = (C × i × A) / 3.6 [m³/s]
11.3 ✏️ Worked Example — Culvert Sizing
Given: Catchment area A = 5 ha | Runoff coefficient C = 0.6 | Rainfall intensity i = 80 mm/hr
Find: Peak discharge Q and required culvert diameter (circular pipe culvert, flow velocity V = 1.5 m/s)
Q = (C × i × A) / 360 = (0.6 × 80 × 5) / 360 = 240/360 = 0.667 m³/s
Step 2: Required cross-sectional area of culvert
A_culvert = Q / V = 0.667 / 1.5 = 0.444 m²
Step 3: Required diameter of circular pipe culvert
A = π/4 × D²
D² = 4A/π = 4 × 0.444 / π = 1.776 / 3.1416 = 0.565
D = √0.565 = 0.752 m ≈ 0.80 m (say 800 mm NP3 RCC pipe culvert)
Step 4: Check — use standard sizes
Nearest standard IRC culvert: 900 mm diameter (round up for safety margin)
Provided velocity at 900 mm = Q/A = 0.667/(π/4×0.81) = 0.667/0.636 = 1.05 m/s < 1.5 m/s ✅
13. Technical Diagrams
Diagram 1: Levelling Field Book Layout & L-Section Concept
Diagram 2: Cross-Section Types — Level, Two-Level, Three-Level
Diagram 3: Mass Haul Diagram — Graphical Representation
14. Key Formulas & Keywords
Levelling (HI Method): HI = RL + BS | RL = HI − IS (or FS) | Check: ΣBS − ΣFS = Last RL − First RL
Level Section (Cutting): A = (B + nh) × h
Two-Level Section: W₁=(b+nh)×s/(s−n) | W₂=(b+nh)×s/(s+n) | A = ½(W₁h₁ + W₂h₂)
Average End Area (Earthwork): V = (A₁+A₂)/2 × L
Prismoidal Formula: V = L/6 × (A₁ + 4A_m + A₂)
Prismoidal Correction: C_p = L/12 × (D₁−D₂)² × n
Deflection Angle (Curve Setting Out): δ = (c × 1718.87)/R minutes | Total = Δ/2 at PT
Curve Length: L = πRΔ/180 | Tangent Length: T = R·tan(Δ/2)
Design CBR: CBR_design = Mean − 1.65 × σ (for 90th percentile)
Rational Formula (Peak Discharge): Q = CiA/360 m³/s (A in hectares)
Culvert Area: A = Q/V | Pipe Diameter: D = √(4A/π)
🔑 Keywords — GATE & SSC One-Liners
- HI method — Height of Instrument; fast; preferred for highway L-sections with many IS readings
- Rise & Fall method — More accurate; complete arithmetic check; preferred for precise levelling
- Benchmark (BM) — Fixed reference point of known elevation (SOI GTS BM)
- TBM — Temporary Benchmark; established every 200–300 m along route from BM
- L-Section — Longitudinal section (profile) of road showing ground levels and grade line
- Cross-section — Section at right angles to centreline; used to calculate cut/fill areas
- Level section — Flat ground across carriageway: A = (B+nh)×h
- Two-level section — Sloping ground on one cross-slope direction
- Average End Area — V = (A₁+A₂)/2 × L; simpler but slightly overestimates
- Prismoidal formula — V = L/6(A₁+4A_m+A₂); more accurate; uses mid-section area
- Mass haul diagram — Cumulative volume vs chainage; rising = cut, falling = fill
- Free haul distance — 30 m (India); no extra charge for earthwork movement within this
- Borrow — Imported earth when fill > cut | Waste/Spoil — Removed earth when cut > fill
- Deflection angle method — Rankine’s method; theodolite at PC; δ = c×1718.87/R minutes
- CBR design value — Mean − 1.65σ (represents 90th percentile for pavement design)
- Rational formula — Q = CiA/360; for catchments ≤ 50 km²
- Aneroid barometer — Reconnaissance survey instrument; approximate elevation ±3–5 m
- Total Station — Preliminary and final survey; measures angles + distances electronically
- LiDAR — Airborne laser; DEM accuracy ±5 cm; replaces conventional levelling on large projects
15. GATE & SSC JE Solved MCQs
(a) ΣBS + ΣFS = Last RL − First RL (b) ΣBS − ΣFS = Last RL − First RL (c) ΣIS = ΣBS (d) None
✅ Answer: (b) ΣBS − ΣFS = Last RL − First RL
(a) B × h (b) (B/2 + nh) × h (c) (B + nh) × h (d) (B + 2nh) × h
✅ Answer: (c) A = (B + nh) × h
(a) Embankment zone (b) Cutting zone (c) Balancing point (d) Borrow zone
✅ Answer: (b) Cutting zone — positive net volumes add to cumulative, making the curve rise
(a) L/4 × (A₁ + A₂ + A_m) (b) L/6 × (A₁ + 4A_m + A₂) (c) L/3 × (A₁ + A_m + A₂) (d) L/2 × (A₁ + A₂)
✅ Answer: (b) V = L/6 × (A₁ + 4A_m + A₂)
(a) Δ (b) Δ/4 (c) Δ/2 (d) 2Δ
✅ Answer: (c) Δ/2 — where Δ is the total deflection angle of the curve
(a) 600 m³ (b) 900 m³ (c) 400 m³ (d) 750 m³
✅ Answer: (b) V = (20+40)/2 × 30 = 30 × 30 = 900 m³
(a) 85.94′ (b) 100′ (c) 172′ (d) 57.3′
✅ Answer: (a) δ = (20 × 1718.87)/200 = 34377.4/200 = 171.89′ ≈ 171.9 minutes = 2°51’54”
(Note: option (c) 172′ is the correct rounded answer — 172 minutes)
16. Frequently Asked Questions (FAQs)
What is the difference between HI method and Rise & Fall method in levelling?
In the Height of Instrument (HI) method, you first calculate HI = RL of station + BS reading, then find RL of all subsequent points as HI − staff reading. It is faster when there are many intermediate sights (as in highway L-section work) because you only need one subtraction per point. The check is ΣBS − ΣFS = Last RL − First RL — but this check does NOT catch errors in intermediate sight readings.
In the Rise and Fall method, you compare consecutive staff readings — if the new reading is less, it’s a rise; if more, it’s a fall. The check is ΣBS − ΣFS = ΣRise − ΣFall = Last RL − First RL — this catches ALL errors including intermediate sights. It is preferred for precise levelling but slower. For highway L-sections with dozens of IS readings, HI method is standard practice.
Why is the Average End Area method less accurate than the Prismoidal formula?
The Average End Area method (V = (A₁+A₂)/2 × L) assumes that the volume between two sections is a prism with constant cross-section equal to the average of the two end areas. This overestimates volume when the cross-section is convex (bulging) between the two stations and underestimates when it is concave. The Prismoidal formula (V = L/6 × (A₁+4A_m+A₂)) accounts for the actual shape by incorporating the mid-section area A_m, making it mathematically exact for prismoidal shapes. On large highway projects, the difference can be 5–10% of total earthwork volume — significant cost impact.
How is the design CBR determined from multiple field samples?
CBR values vary significantly along a highway route due to soil variability. For pavement design, you cannot use the average CBR (this would mean 50% of the road is under-designed). IRC 37 recommends using the design CBR = Mean − 1.65 × Standard Deviation when sample size n ≥ 6. This represents approximately the 10th percentile value — meaning 90% of the road section has a CBR equal to or higher than this value. Only 10% of the road will have a subgrade slightly weaker than designed. For small sample sizes (n < 6), IRC SP-20 suggests using the lowest CBR value measured as a conservative design value.
What is free haul distance and how is it used in highway contracts?
Free haul distance (FHD) is the distance within which the contractor is required to move excavated earth as part of the basic earthwork rate — no extra charge is levied. In India, the standard FHD is typically 30 metres as per MoRTH specifications. If earth must be moved more than FHD (called overhaul), the contractor charges an additional overhaul rate per 100 m³ per 100 m of extra distance. The mass haul diagram is used to identify all zones where overhaul is required, calculate total overhaul quantities, and determine the most economical direction of hauling to minimise total haul cost.
How is a horizontal curve set out in the field using the deflection angle method?
In the deflection angle method (Rankine’s method): (1) Set up the theodolite at PC (Point of Curvature). (2) Set the horizontal circle to 0°00′ sighting back along the rear tangent. (3) Calculate the deflection angle per chord: δ = (c × 1718.87)/R minutes, where c = chord length and R = radius. (4) Set the telescope to deflection angle δ for the first point; the chainman stretches a tape of chord length c from PC — the peg goes where the tape end meets the line of sight. (5) For subsequent points, add δ cumulatively (2δ, 3δ, 4δ…). (6) At PT, total deflection = Δ/2 — this is the field check that the curve has been correctly set out.
Level section: A=(B+nh)×h | Avg End Area: V=(A₁+A₂)/2×L | Prismoidal: V=L/6(A₁+4Am+A₂)
HI check: ΣBS−ΣFS = Last RL−First RL | Deflection angle: δ = c×1718.87/R min | Total at PT: Δ/2
Design CBR: Mean − 1.65σ | Rational Q: CiA/360 | Free haul: 30 m (India)
Mass haul rising: Cut zone | Falling: Fill zone | Crosses zero: Balance point
