- 2.1 Stress — Normal and Shear
- 2.2 Matrix Representation — 3D Stress Tensor and Strains
- 2.3 Differential Form of Strains
- 2.4 Allowable Stresses and Factor of Safety
- 2.5 Saint Venant Principal
- 2.6 Hooke’s Law + 2.7 Four Elastic Constants (E, G, K, μ)
- 2.7.1 Relationships Between Elastic Constants
- 2.8 Hooke’s Law Applications + 2.9 Volumetric Strain
- 2.10 Deflection of Axially Loaded Members
- 2.11 Statically Indeterminate Structures
- 2.13 Temperature Stresses
- 2.15 Strain Energy
2.1 Stress — Normal and Shear
2.1.1 Normal Stress
Normal stresses are always normal to the cross-section. Two types:
Produced when axial force acts at CG. Uniform across cross-section for prismatic body. Tensile = +ve, Compressive = −ve.
Produced by bending moment. Varies linearly from zero at NA to maximum at extreme fibre. Tensile = +ve, Compressive = −ve.
2.1.2 Shear Stress or Tangential Stress
Resistance offered by material against shearing force. Two types: direct shear (τ = S/A) and torsional shear (due to torque).
τ_xy = τ_yx (from moment equilibrium)
2.2 Matrix Representation of Stress and Strain
2.2.1 Stress Tensor — 3D Stress Element
Stress and strain are second order tensor quantities. In a 3D loaded body, at a point three mutually perpendicular planes exist. At each plane there are 3 stress components — 1 normal + 2 shear. Total: 9 components, but due to complementarity only 6 are independent.
| σ_xx τ_xy τ_xz |
| τ_yx σ_yy τ_yz |
| τ_zx τ_zy σ_zz |
τ = Shear stress (off-diagonal)
τ_xy=τ_yx, τ_xz=τ_zx, τ_yz=τ_zy
| σ_xx τ_xy |
| τ_yx σ_yy |
Used in most 2D structural problems
- Normal stresses: σ_xx, σ_yy, σ_zz — first letter = plane, second letter = direction
- Shear stresses: τ_xy — x = plane, y = direction of stress
- 3D stresses are called Triaxial stresses
2.2.2 Matrix Representation of Strains
Strain in direction of applied force
Strain perpendicular to applied force
Angular deformation due to shear
| φ_yx/2 ε_yy φ_yz/2 |
| φ_zx/2 φ_zy/2 ε_zz |
Linear strain of diagonal = φ/2 (half of shear strain in the body)
2.3 Differential Form of Strains
If point P moves to position (u, v, w) when force F is applied, linear strains in x, y, z directions are given by partial derivatives of displacements:
ε_yy = ∂v/∂y
ε_zz = ∂w/∂z
φ_yz = ∂v/∂z + ∂w/∂y
φ_xz = ∂u/∂z + ∂w/∂x
2.4 Allowable Stresses and Factor of Safety
σ_y = yield stress
Failure by yielding
σ_u = ultimate stress
Failure by fracture
Except at extreme ends of a bar carrying direct loading, stress distribution over cross-section is uniform.
σ_max at 2-2 = 1.027 σ_avg
σ_max at 3-3 = σ_avg
2.6 Hooke’s Law + 2.7 Elastic Constants (E, G, K, μ)
2.6 Hooke’s Law
Under direct loading, within proportionality limit, stress is directly proportional to strain.
2.7 The Four Elastic Constants
Fig. 2.1 — Four elastic constants. E = slope of σ-ε (steel = 2×10⁵ N/mm²). G = shear stress/shear strain. K = inversely proportional to compressibility. μ = 0.25–0.42 for metals. Hooke’s law valid only up to limit of proportionality.
2.7.1 Relationships Between the Four Elastic Constants
- The ratio E/K for most metals is about more than one third
- For homogeneous & isotropic material: only 2 independent constants (E and μ)
- For orthotropic material: 9 independent constants; Anisotropic: 21
- For metals: μ ≤ 0.42 → if ΔV = 0, then σ_x + σ_y + σ_z = 0 (as μ ≠ 0.5)
- Pure rubber: μ = 0.5 (perfectly incompressible)
2.8 Applications of Hooke’s Law + 2.9 Volumetric Strain
Case I — Uniaxial Loading (σ_x applied)
ε_y = −μ·σ_x/E (lateral strain in y)
ε_z = −μ·σ_x/E (lateral strain in z)
Case II — Triaxial Loading (σ_x, σ_y, σ_z applied)
ε_y = σ_y/E − μ(σ_x/E) − μ(σ_z/E)
ε_z = σ_z/E − μ(σ_x/E) − μ(σ_y/E)
2.9 Volumetric Strain (ε_V)
Volumetric strain = ratio of change in volume to original volume. Also called Dilatation.
= ε_x + ε_y + ε_z
= (σ_x+σ_y+σ_z)(1−2μ)/E
(ε_l = longitudinal
ε_d = diametral)
(ε_d = diametral
strain)
2.10 Deflection of Axially Loaded Members
AE = axial rigidity | AE/L = axial stiffness
If D₁ = D₂ = D → Δ = PL/AE (uniform)
γ = unit weight | W = γAL = total weight
Compatibility: δ₁ = δ₂
P₁ = PA₁E₁/(A₁E₁+A₂E₂)
P₂ = PA₂E₂/(A₁E₁+A₂E₂)
Δ = PL/(A₁E₁+A₂E₂)
2.10.1 Principle of Superposition
In a linear elastic structure, total displacements (or stresses) from multiple simultaneous loads = algebraic sum of displacements (or stresses) caused by each load acting independently.
2.11 Statically Indeterminate Axial Loaded Structures
Structures where static equilibrium equations alone are insufficient to find internal forces. Solved using Flexibility Approach (D_k < D_o — deflection compatibility) or Stiffness Approach. Extra equations are written in the form of deflection, slope and rotation — called compatibility equations.
Step 2: Compatibility → Total deformation = 0 (fixed-fixed)
i.e., P₁L₁/A₁E₁ + P₂L₂/A₂E₂ = 0
2.13 Temperature Stresses
If bar is rested over frictionless surface, free thermal expansion/contraction occurs without stress. If bar is constrained between fixed supports, thermal stresses develop.
Fig. 2.2 — Temperature stresses in a constrained bar. σ = EαT regardless of case. From source: thermal stresses are independent of member dimensions.
2.15 Strain Energy
Energy stored in the body due to deformation against applied load. Denoted by U. Strain energy density = strain energy per unit volume.
Chapter 2: Simple Stress-strain and Elastic Constants — Strength of Materials · MADE EASY Postal Study Package 2019
