RCC numerical – Calculate the ultimate moment of resistance of R.C. beam

Calculate the ultimate moment of resistance of R.C. beam 250 mm Γ— 500 mm. Reinforcement of 1256 mm2 is placed at a distance of 30 mm from the bottom face. Use M20 concrete and Fe250 steel.

To calculate the ultimate moment of resistance for a reinforced concrete (R.C.) beam, we follow these steps:

  1. Determine the effective depth (𝑑):

    • Overall depth of the beam (𝐷) = 500 mm
    • Cover to the reinforcement = 30 mm (from the bottom face)
    • Effective depth (𝑑) = π·βˆ’cover = 500 mm – 30 mm = 470 mm
  2. Calculate the design strengths of the materials:

    • For M20 concrete: π‘“π‘π‘˜=20 MPa
      • Design strength of concrete, 𝑓𝑐𝑑=π‘“π‘π‘˜1.5=201.5=13.33 MPa
    • For Fe250 steel: 𝑓𝑦=250 MPa
      • Design strength of steel, 𝑓𝑦𝑑=𝑓𝑦1.5=2501.5=166.67 MPa
  3. Calculate the effective area of steel reinforcement (𝐴𝑠):

    • Given 𝐴𝑠=1256 mm2
  4. Calculate the depth of the neutral axis (π‘₯): To simplify, we assume that the beam is under-reinforced. For under-reinforced sections, the neutral axis depth can be approximated using:

    π‘₯=𝐴𝑠⋅𝑓𝑦𝑑0.87⋅𝑓𝑐𝑑⋅𝑏

    where:

    • 𝑏 = width of the beam = 250 mm

    π‘₯=1256β‹…166.670.87β‹…13.33β‹…250π‘₯β‰ˆ0.636 mβ‰ˆ636 mm

    Since the calculated π‘₯ exceeds the effective depth (𝑑), this indicates that the beam is in a condition of over-reinforcement. For an over-reinforced section, the neutral axis is taken at the maximum depth of π‘₯=0.48𝐷.

    Hence, π‘₯=0.48β‹…500=240 mm (as assumed, this value of π‘₯ is used).

  5. Calculate the lever arm (𝑧): The lever arm is approximately given by:

    𝑧=π‘‘βˆ’π‘₯2𝑧=470βˆ’2402=470βˆ’120=350 mm

  6. Calculate the ultimate moment of resistance (𝑀𝑒):

    𝑀𝑒=𝐴𝑠⋅𝑓𝑦𝑑⋅𝑧𝑀𝑒=1256β‹…166.67β‹…350π‘€π‘’β‰ˆ73.29 kNm

    Thus, the ultimate moment of resistance for the given R.C. beam is approximately 73.29 kNm.

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To calculate the ultimate moment of resistance for a reinforced concrete (R.C.) beam, we follow these steps:

  1. Determine the effective depth (𝑑):

    • Overall depth of the beam (𝐷) = 500 mm
    • Cover to the reinforcement = 30 mm (from the bottom face)
    • Effective depth (𝑑) = π·βˆ’cover = 500 mm – 30 mm = 470 mm
  2. Calculate the design strengths of the materials:

    • For M20 concrete: π‘“π‘π‘˜=20 MPa
      • Design strength of concrete, 𝑓𝑐𝑑=π‘“π‘π‘˜1.5=201.5=13.33 MPa
    • For Fe250 steel: 𝑓𝑦=250 MPa
      • Design strength of steel, 𝑓𝑦𝑑=𝑓𝑦1.5=2501.5=166.67 MPa
  3. Calculate the effective area of steel reinforcement (𝐴𝑠):

    • Given 𝐴𝑠=1256 mm2
  4. Calculate the depth of the neutral axis (π‘₯): To simplify, we assume that the beam is under-reinforced. For under-reinforced sections, the neutral axis depth can be approximated using:

    π‘₯=𝐴𝑠⋅𝑓𝑦𝑑0.87⋅𝑓𝑐𝑑⋅𝑏

    where:

    • 𝑏 = width of the beam = 250 mm

    π‘₯=1256β‹…166.670.87β‹…13.33β‹…250π‘₯β‰ˆ0.636 mβ‰ˆ636 mm

    Since the calculated π‘₯ exceeds the effective depth (𝑑), this indicates that the beam is in a condition of over-reinforcement. For an over-reinforced section, the neutral axis is taken at the maximum depth of π‘₯=0.48𝐷.

    Hence, π‘₯=0.48β‹…500=240 mm (as assumed, this value of π‘₯ is used).

  5. Calculate the lever arm (𝑧): The lever arm is approximately given by:

    𝑧=π‘‘βˆ’π‘₯2𝑧=470βˆ’2402=470βˆ’120=350 mm

  6. Calculate the ultimate moment of resistance (𝑀𝑒):

    𝑀𝑒=𝐴𝑠⋅𝑓𝑦𝑑⋅𝑧𝑀𝑒=1256β‹…166.67β‹…350π‘€π‘’β‰ˆ73.29 kNm

    Thus, the ultimate moment of resistance for the given R.C. beam is approximately 73.29 kNm.

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